void main()
{
int i0,RMB;
int n1,n2,n5;
printf("请输入要转换的数额:");
scanf("%d",&RMB);
for(n10;n1<RMB;n1++){
内for(n50;n5<2;n5++){
if((RMB-n1-5*n5)%20){
n2(RMB-n1-5*n5)/2;
if(n2>0){
printf("1元%d张容,2元%d张,5元%d张\n",n1,n2,n5);
i++;
}
}
}
}
printf("所以,总共有%d种换法\n",i);
}